Infosys Aptitude Test Questions and Answers 2025: Infosys conducts aptitude tests as part of its recruitment process for freshers. The aptitude section evaluates problem-solving, logical reasoning, and quantitative skills. In this article, we have compiled Infosys Aptitude Questions with detailed solutions across all important topics like Percentages, Averages, Profit & Loss, Ratio & Proportion, Time & Work, Speed & Distance, Probability, Permutations & Combinations, and Logical Reasoning.
These questions will help you practice and prepare effectively for Infosys Placement 2025.
Check Below Infosys Aptitude Test Questions and Answers 2025
Set 1
Q1. A batsman scored 110 runs which included 3 boundaries and 8 sixes.
What percent of his total score did he make by running between the wickets?
A) 45%
B) 45 (5/11)%
C) 54 (6/11)%
D) 55%
✅ Answer: 45 (5/11)%
📖 Explanation: Runs by running = 110 – (3×4 + 8×6) = 110 – 60 = 50.
Percentage = (50/110) × 100 = 45 (5/11)%.
Q2. Two students appeared at an examination. One secured 9 marks more than the other and his marks were 56% of the sum of their marks. Find their marks.
A) 39, 30
B) 41, 32
C) 42, 33
D) 43, 34
✅ Answer: 42, 33
📖 Explanation: Let marks = (x+9) and x.
x+9 = 56% of (x+9+x).
25(x+9) = 14(2x+9).
x=33 → Marks = 42, 33.
Q3. A fruit seller had some apples. He sells 40% and still has 420 left. Originally, he had:
A) 588
B) 600
C) 672
D) 700
✅ Answer: 700
📖 Explanation: 60% of x = 420 → x = 420×100/60 = 700.
Q4. If A = x% of y and B = y% of x, then:
A) A < B
B) A > B
C) Cannot be determined
D) If x<y, then A>B
E) None
✅ Answer: None of these
📖 Explanation: A = B = (xy)/100.
Q5. If 20% of a = b, then b% of 20 is equal to:
A) 4% of a
B) 5% of a
C) 20% of a
D) None
✅ Answer: 4% of a
📖 Explanation: 20% of a = b → b% of 20 = (b/100)×20 = 4% of a.
Q6. In a school, 20% of students are below 8 years. No. above 8 years = 2/3 of no. of exactly 8 years = 48. Find total students.
A) 72
B) 80
C) 120
D) 150
E) 100
✅ Answer: 100
📖 Explanation: Let total = x.
Above 8 = 80% of x = 48 + (2/3)×48 = 80.
x=100.
Q7. Two numbers A and B are such that 5% of A + 4% of B = â…” of (6% of A + 8% of B). Find ratio A:B.
A) 2:3
B) 1:1
C) 3:4
D) 4:3
✅ Answer: 1:1
Q8. How much is 60% of 50 greater than 40% of 30?
A) 18
B) 13
C) 15
D) 20
✅ Answer: 18
📖 Explanation: (60/100×50) – (40/100×30) = 30–12 = 18.
Q9. Tax on a commodity reduced by 20%, consumption increased 15%. Effect on revenue?
A) Increases 8%
B) Decreases 8%
C) No change
D) Increases 10%
E) None
✅ Answer: Decreases 8%
📖 Explanation: Original revenue = 100×100 = 10000.
New revenue = 80×115 = 9200.
Drop = 800 → 8%.
Q10. Full marks = 500. A got 10% less than B, B got 25% more than C, C got 20% less than D. If A=360, what % of full marks did D get?
A) 70%
B) 90%
C) 80%
D) 75%
✅ Answer: 80%
📖 Explanation: Ratio: A:B:C:D = 90:100:80:100.
A=360 → D=400 → (400/500)×100=80%.
Set 2: Percentages – Application
Q11. In a competitive exam, 5% candidates failed in Mathematics, 8% failed in English, while 2% failed in both. If 1800 passed in both subjects, find total candidates.
A) 2000
B) 2100
C) 2200
D) 2300
✅ Answer: 2000
Explanation: Failed = 5+8–2 = 11%.
Passed = 89%.
89% = 1800 → 100% = 1800×100/89 ≈ 2022 ~ 2000.
Q12. A student multiplied a number by 3/5 instead of 5/3. What is the % error?
A) 64%
B) 34%
C) 74%
D) 54%
✅ Answer: 64%
📖 Explanation: Correct result = (5/3)x.
Wrong result = (3/5)x.
Error = [(5/3 – 3/5)/ (5/3)]×100 = (16/15 ÷ 5/3)×100 = 64%.
Q13. Two candidates contested. One got 55% votes and won by 270 votes. Find total valid votes.
A) 1200
B) 1250
C) 1350
D) 1500
✅ Answer: 1500
📖 Explanation: Difference = 55% – 45% = 10%.
10% = 270 → 100% = 2700.
Q14. A’s salary is 25% more than B’s. How much % is B’s salary less than A’s?
A) 15%
B) 20%
C) 25%
D) 30%
✅ Answer: 20%
📖 Explanation: Assume B=100 → A=125.
% less = (25/125)×100 = 20%.
Q15. A is 40% more efficient than B. Together they can complete a work in 25 days. In how many days will A alone finish it?
A) 40
B) 45
C) 50
D) 35
✅ Answer: 35
📖 Explanation: Ratio efficiency = A:B = 140:100 = 7:5.
Together efficiency = 12.
Time = 25 days → Work = 300 units.
A’s 1 day = 7 → 300/7 ≈ 42.8 → option nearest 35 (approx in given).
Set 3: Percentages – Mixtures
Q16. A shopkeeper buys 80 pens at 12 for ₹120 and sells at 10 for ₹132. Find gain %.
A) 30%
B) 32%
C) 33%
D) 34%
✅ Answer: 33%
📖 Explanation: CP per pen = 120/12 = 10.
SP per pen = 132/10 = 13.2.
Profit% = (3.2/10)×100 = 32%.
Q17. A man spends 35% on food, 25% on house rent, 15% on clothes, 5% on travel. He saves ₹3000. Find income.
A) 8000
B) 10000
C) 12000
D) 15000
✅ Answer: 12000
📖 Explanation: Expenses% = 35+25+15+5 = 80%.
Savings = 20% = 3000 → 100% = 15000.
Q18. A’s income is 20% less than B’s. By how much % is B’s income more than A’s?
A) 20%
B) 25%
C) 30%
D) 15%
✅ Answer: 25%
📖 Explanation: A=80, B=100.
% more = (20/80)×100 = 25%.
Q19. A fruit seller had 420 apples left after selling 40% of total. Find original apples.
A) 588
B) 600
C) 672
D) 700
✅ Answer: 700
Q20. 20% of a = b. Find b% of 20.
A) 4% of a
B) 5% of a
C) 20% of a
D) None
✅ Answer: 4% of a
Set 4: Percentages – Profit & Loss
Q21. A shopkeeper cheats by giving 900 gm instead of 1 kg. Find his gain %.
A) 11 (1/9)%
B) 10%
C) 11%
D) 12%
✅ Answer: 11 (1/9)%
📖 Explanation: CP of 900g = 900.
SP = 1000.
Profit% = 100/900×100 = 11 (1/9)%.
Q22. A salary increased by 20% then decreased by 25%. Net effect?
A) 5% increase
B) 5% decrease
C) 10% decrease
D) 20% decrease
✅ Answer: 10% decrease
📖 Explanation: 100 → 120 → 90.
Net = 10% fall.
Q23. A shopkeeper sold 2 articles at ₹300 each. One at 20% profit, another at 20% loss. Find net % profit/loss.
A) 4% profit
B) 4% loss
C) 5% profit
D) 5% loss
✅ Answer: 4% loss
📖 Explanation: CP1 = 300×100/120=250.
CP2 = 300×100/80=375.
Total CP=625, SP=600.
Loss=25 → 25/625×100=4%.
Q24. The price of sugar rises by 25%. By how much % should consumption be reduced to keep expenditure same?
A) 20%
B) 25%
C) 30%
D) 33 (1/3)%
✅ Answer: 20%
📖 Explanation: Formula: Reduction = (25/125)×100 = 20%.
Q25. A sum is increased by 10%, then again by 10%. By how much % is total increased?
A) 19%
B) 20%
C) 21%
D) 22%
✅ Answer: 21%
📖 Explanation: Net% = a+b+(ab/100).
=10+10+(10×10/100)=21%.
Set 5: Percentages – Advanced
Q26. The population of a town increases by 10% annually. If at end of 2 years it is 12100, what was initial?
A) 10000
B) 11000
C) 12000
D) 9000
✅ Answer: 10000
📖 Explanation: P×(1.1)^2 = 12100 → P=10000.
Q27. A’s salary is 20% more than B’s. By what % is B’s salary less than A’s?
A) 16 (2/3)%
B) 20%
C) 25%
D) 10%
✅ Answer: 16 (2/3)%
📖 Explanation: Assume B=100 → A=120.
% less = 20/120×100=16 (2/3)%.
Q28. Ram’s marks were 20% less than Shyam’s. By what % were Shyam’s marks more than Ram’s?
A) 20%
B) 25%
C) 30%
D) 15%
✅ Answer: 25%
Q29. A man spends 35% on food, 25% on rent, 15% on clothes, 5% on travel. He saves ₹3000. Find income.
A) 8000
B) 10000
C) 12000
D) 15000
✅ Answer: 15000
Q30. A’s salary is 25% less than B’s. By how much % is B’s more than A’s?
A) 20%
B) 25%
C) 33 (1/3)%
D) 30%
✅ Answer: 33 (1/3)%
